Base | Representation |
---|---|
bin | 11001110010100110111101… |
… | …01011011011010011101001 |
3 | 21102210211222220120211222012 |
4 | 30321103132223123103221 |
5 | 24413202230412234002 |
6 | 320342135130205305 |
7 | 14642325533536463 |
oct | 1471233653332351 |
9 | 242724886524865 |
10 | 56714484102377 |
11 | 17086528806682 |
12 | 643b791b83835 |
13 | 25851cac0888a |
14 | 1000dd21cd133 |
15 | 68541955ad52 |
hex | 3394deadb4e9 |
56714484102377 has 2 divisors, whose sum is σ = 56714484102378. Its totient is φ = 56714484102376.
The previous prime is 56714484102317. The next prime is 56714484102391. The reversal of 56714484102377 is 77320148441765.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 56349884302336 + 364599800041 = 7506656^2 + 603821^2 .
It is a cyclic number.
It is not a de Polignac number, because 56714484102377 - 212 = 56714484098281 is a prime.
It is not a weakly prime, because it can be changed into another prime (56714484102307) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 28357242051188 + 28357242051189.
It is an arithmetic number, because the mean of its divisors is an integer number (28357242051189).
Almost surely, 256714484102377 is an apocalyptic number.
It is an amenable number.
56714484102377 is a deficient number, since it is larger than the sum of its proper divisors (1).
56714484102377 is an equidigital number, since it uses as much as digits as its factorization.
56714484102377 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 31610880, while the sum is 59.
The spelling of 56714484102377 in words is "fifty-six trillion, seven hundred fourteen billion, four hundred eighty-four million, one hundred two thousand, three hundred seventy-seven".
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