Base | Representation |
---|---|
bin | 11001110100101000010011… |
… | …00101101010100000011001 |
3 | 21110001111020021001011120201 |
4 | 30322110021211222200121 |
5 | 24420321433403120133 |
6 | 320434101353222201 |
7 | 14650334362561264 |
oct | 1472241145524031 |
9 | 243044207034521 |
10 | 56783923488793 |
11 | 17102a21501436 |
12 | 6451131101961 |
13 | 258b916167ac7 |
14 | 10044dc591cdb |
15 | 68713082dd7d |
hex | 33a50996a819 |
56783923488793 has 2 divisors, whose sum is σ = 56783923488794. Its totient is φ = 56783923488792.
The previous prime is 56783923488731. The next prime is 56783923488833. The reversal of 56783923488793 is 39788432938765.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 54336535454224 + 2447388034569 = 7371332^2 + 1564413^2 .
It is a cyclic number.
It is not a de Polignac number, because 56783923488793 - 245 = 21599551399961 is a prime.
It is not a weakly prime, because it can be changed into another prime (56783923458793) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 28391961744396 + 28391961744397.
It is an arithmetic number, because the mean of its divisors is an integer number (28391961744397).
Almost surely, 256783923488793 is an apocalyptic number.
It is an amenable number.
56783923488793 is a deficient number, since it is larger than the sum of its proper divisors (1).
56783923488793 is an equidigital number, since it uses as much as digits as its factorization.
56783923488793 is an evil number, because the sum of its binary digits is even.
The product of its digits is 13168189440, while the sum is 82.
The spelling of 56783923488793 in words is "fifty-six trillion, seven hundred eighty-three billion, nine hundred twenty-three million, four hundred eighty-eight thousand, seven hundred ninety-three".
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