Base | Representation |
---|---|
bin | 110100111010100001… |
… | …001011001101100011 |
3 | 12102122121222122001011 |
4 | 310322201023031203 |
5 | 1412324441200201 |
6 | 42033455321351 |
7 | 4050651002266 |
oct | 647241131543 |
9 | 172577878034 |
10 | 56816350051 |
11 | 221063917aa |
12 | b017820257 |
13 | 5485cc4656 |
14 | 2a6db22cdd |
15 | 1727ed4151 |
hex | d3a84b363 |
56816350051 has 2 divisors, whose sum is σ = 56816350052. Its totient is φ = 56816350050.
The previous prime is 56816350043. The next prime is 56816350061. The reversal of 56816350051 is 15005361865.
56816350051 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 56816350051 - 23 = 56816350043 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 56816349986 and 56816350013.
It is not a weakly prime, because it can be changed into another prime (56816350061) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 28408175025 + 28408175026.
It is an arithmetic number, because the mean of its divisors is an integer number (28408175026).
Almost surely, 256816350051 is an apocalyptic number.
56816350051 is a deficient number, since it is larger than the sum of its proper divisors (1).
56816350051 is an equidigital number, since it uses as much as digits as its factorization.
56816350051 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 108000, while the sum is 40.
The spelling of 56816350051 in words is "fifty-six billion, eight hundred sixteen million, three hundred fifty thousand, fifty-one".
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