Base | Representation |
---|---|
bin | 11001110110010000110110… |
… | …01110000000011111010001 |
3 | 21110020212010002020001201220 |
4 | 30323020123032000133101 |
5 | 24422231412241231423 |
6 | 320515543225515253 |
7 | 14654362344025350 |
oct | 1473103316003721 |
9 | 243225102201656 |
10 | 56840053852113 |
11 | 17124805645154 |
12 | 645bb97042b29 |
13 | 2593cbccb853c |
14 | 1007105147997 |
15 | 6888184ac9e3 |
hex | 33b21b3807d1 |
56840053852113 has 64 divisors (see below), whose sum is σ = 88921869189120. Its totient is φ = 31619492610048.
The previous prime is 56840053852103. The next prime is 56840053852139. The reversal of 56840053852113 is 31125835004865.
It is not a de Polignac number, because 56840053852113 - 25 = 56840053852081 is a prime.
It is a super-2 number, since 2×568400538521132 (a number of 28 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (56840053852103) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 495544273 + ... + 495658961.
It is an arithmetic number, because the mean of its divisors is an integer number (1389404206080).
Almost surely, 256840053852113 is an apocalyptic number.
It is an amenable number.
56840053852113 is a deficient number, since it is larger than the sum of its proper divisors (32081815337007).
56840053852113 is a wasteful number, since it uses less digits than its factorization.
56840053852113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 116558.
The product of its (nonzero) digits is 3456000, while the sum is 51.
Adding to 56840053852113 its reverse (31125835004865), we get a palindrome (87965888856978).
The spelling of 56840053852113 in words is "fifty-six trillion, eight hundred forty billion, fifty-three million, eight hundred fifty-two thousand, one hundred thirteen".
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