Base | Representation |
---|---|
bin | 1101100011011… |
… | …0000010010001 |
3 | 10221221222220101 |
4 | 3120312002101 |
5 | 104023010213 |
6 | 5350212401 |
7 | 1260112132 |
oct | 330660221 |
9 | 127858811 |
10 | 56844433 |
11 | 2a0a6078 |
12 | 17054101 |
13 | ba13879 |
14 | 7799c89 |
15 | 4eccbdd |
hex | 3636091 |
56844433 has 2 divisors, whose sum is σ = 56844434. Its totient is φ = 56844432.
The previous prime is 56844401. The next prime is 56844439. The reversal of 56844433 is 33444865.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 47651409 + 9193024 = 6903^2 + 3032^2 .
It is a cyclic number.
It is not a de Polignac number, because 56844433 - 25 = 56844401 is a prime.
It is equal to p3385774 and since 56844433 and 3385774 have the same sum of digits, it is a Honaker prime.
It is a junction number, because it is equal to n+sod(n) for n = 56844392 and 56844401.
It is not a weakly prime, because it can be changed into another prime (56844439) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (11) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 28422216 + 28422217.
It is an arithmetic number, because the mean of its divisors is an integer number (28422217).
Almost surely, 256844433 is an apocalyptic number.
It is an amenable number.
56844433 is a deficient number, since it is larger than the sum of its proper divisors (1).
56844433 is an equidigital number, since it uses as much as digits as its factorization.
56844433 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 138240, while the sum is 37.
The square root of 56844433 is about 7539.5247197685. The cubic root of 56844433 is about 384.4996772978.
The spelling of 56844433 in words is "fifty-six million, eight hundred forty-four thousand, four hundred thirty-three".
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