Base | Representation |
---|---|
bin | 100001111001011… |
… | …011110000101001 |
3 | 1110122010011021122 |
4 | 201321123300221 |
5 | 2131042012131 |
6 | 132233145025 |
7 | 20043622163 |
oct | 4171336051 |
9 | 1418104248 |
10 | 568704041 |
11 | 272022844 |
12 | 13a55b175 |
13 | 90a8ba89 |
14 | 5575b933 |
15 | 34dd9d7b |
hex | 21e5bc29 |
568704041 has 2 divisors, whose sum is σ = 568704042. Its totient is φ = 568704040.
The previous prime is 568703999. The next prime is 568704079. The reversal of 568704041 is 140407865.
568704041 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 430147600 + 138556441 = 20740^2 + 11771^2 .
It is a cyclic number.
It is not a de Polignac number, because 568704041 - 26 = 568703977 is a prime.
It is a Chen prime.
It is a junction number, because it is equal to n+sod(n) for n = 568703992 and 568704010.
It is not a weakly prime, because it can be changed into another prime (568704341) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 284352020 + 284352021.
It is an arithmetic number, because the mean of its divisors is an integer number (284352021).
Almost surely, 2568704041 is an apocalyptic number.
It is an amenable number.
568704041 is a deficient number, since it is larger than the sum of its proper divisors (1).
568704041 is an equidigital number, since it uses as much as digits as its factorization.
568704041 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 26880, while the sum is 35.
The square root of 568704041 is about 23847.5164535010. The cubic root of 568704041 is about 828.5055806102.
The spelling of 568704041 in words is "five hundred sixty-eight million, seven hundred four thousand, forty-one".
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