Base | Representation |
---|---|
bin | 101001011010111011110… |
… | …1111000100110000000011 |
3 | 202011020012211202001012011 |
4 | 1102311313233010300003 |
5 | 1221232414131334011 |
6 | 20035131012513351 |
7 | 1125202615544425 |
oct | 122656757046003 |
9 | 22136184661164 |
10 | 5692840496131 |
11 | 18a5358058a08 |
12 | 77b38891b857 |
13 | 323aa917c589 |
14 | 15976bc90815 |
15 | 9d13cea4621 |
hex | 52d77bc4c03 |
5692840496131 has 2 divisors, whose sum is σ = 5692840496132. Its totient is φ = 5692840496130.
The previous prime is 5692840496089. The next prime is 5692840496143. The reversal of 5692840496131 is 1316940482965.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 5692840496131 - 225 = 5692806941699 is a prime.
It is a super-2 number, since 2×56928404961312 (a number of 26 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (5692840476131) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2846420248065 + 2846420248066.
It is an arithmetic number, because the mean of its divisors is an integer number (2846420248066).
Almost surely, 25692840496131 is an apocalyptic number.
5692840496131 is a deficient number, since it is larger than the sum of its proper divisors (1).
5692840496131 is an equidigital number, since it uses as much as digits as its factorization.
5692840496131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 11197440, while the sum is 58.
The spelling of 5692840496131 in words is "five trillion, six hundred ninety-two billion, eight hundred forty million, four hundred ninety-six thousand, one hundred thirty-one".
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