Base | Representation |
---|---|
bin | 110101000101010100… |
… | …001000011000010001 |
3 | 12110010020210222120001 |
4 | 311011110020120101 |
5 | 1413212323324303 |
6 | 42103445450001 |
7 | 4055310404641 |
oct | 650524103021 |
9 | 173106728501 |
10 | 56997479953 |
11 | 22199656337 |
12 | b068410901 |
13 | 54b46a28cb |
14 | 2a89bd2521 |
15 | 1738d6231d |
hex | d45508611 |
56997479953 has 2 divisors, whose sum is σ = 56997479954. Its totient is φ = 56997479952.
The previous prime is 56997479921. The next prime is 56997479989. The reversal of 56997479953 is 35997479965.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 43518966544 + 13478513409 = 208612^2 + 116097^2 .
It is a cyclic number.
It is not a de Polignac number, because 56997479953 - 25 = 56997479921 is a prime.
It is not a weakly prime, because it can be changed into another prime (56997474953) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 28498739976 + 28498739977.
It is an arithmetic number, because the mean of its divisors is an integer number (28498739977).
Almost surely, 256997479953 is an apocalyptic number.
It is an amenable number.
56997479953 is a deficient number, since it is larger than the sum of its proper divisors (1).
56997479953 is an equidigital number, since it uses as much as digits as its factorization.
56997479953 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 578680200, while the sum is 73.
The spelling of 56997479953 in words is "fifty-six billion, nine hundred ninety-seven million, four hundred seventy-nine thousand, nine hundred fifty-three".
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