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57030141301 = 78147163043
BaseRepresentation
bin110101000111010000…
…101110010101110101
312110012112021100111121
4311013100232111311
51413244204010201
642111013503541
74056155126350
oct650720562565
9173175240447
1057030141301
1122206034291
12b077341bb1
1354bb39a053
142a90295297
15173bb649a1
hexd4742e575

57030141301 has 4 divisors (see below), whose sum is σ = 65177304352. Its totient is φ = 48882978252.

The previous prime is 57030141299. The next prime is 57030141307. The reversal of 57030141301 is 10314103075.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 57030141301 - 21 = 57030141299 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (57030141307) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4073581515 + ... + 4073581528.

It is an arithmetic number, because the mean of its divisors is an integer number (16294326088).

Almost surely, 257030141301 is an apocalyptic number.

It is an amenable number.

57030141301 is a deficient number, since it is larger than the sum of its proper divisors (8147163051).

57030141301 is an equidigital number, since it uses as much as digits as its factorization.

57030141301 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 8147163050.

The product of its (nonzero) digits is 1260, while the sum is 25.

Adding to 57030141301 its reverse (10314103075), we get a palindrome (67344244376).

The spelling of 57030141301 in words is "fifty-seven billion, thirty million, one hundred forty-one thousand, three hundred one".

Divisors: 1 7 8147163043 57030141301