Base | Representation |
---|---|
bin | 101001100000001101001… |
… | …1110011000110000000011 |
3 | 202012022102202210010201121 |
4 | 1103000122132120300003 |
5 | 1221424110122224103 |
6 | 20044242201013111 |
7 | 1126053264213034 |
oct | 123003236306003 |
9 | 22168382703647 |
10 | 5704160742403 |
11 | 18aa137039542 |
12 | 781607a84197 |
13 | 324b91543256 |
14 | 15a1234c4a8b |
15 | 9d5a1c016bd |
hex | 5301a798c03 |
5704160742403 has 2 divisors, whose sum is σ = 5704160742404. Its totient is φ = 5704160742402.
The previous prime is 5704160742373. The next prime is 5704160742419. The reversal of 5704160742403 is 3042470614075.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 5704160742403 - 29 = 5704160741891 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 5704160742403.
It is not a weakly prime, because it can be changed into another prime (5704160742703) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2852080371201 + 2852080371202.
It is an arithmetic number, because the mean of its divisors is an integer number (2852080371202).
Almost surely, 25704160742403 is an apocalyptic number.
5704160742403 is a deficient number, since it is larger than the sum of its proper divisors (1).
5704160742403 is an equidigital number, since it uses as much as digits as its factorization.
5704160742403 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 564480, while the sum is 43.
The spelling of 5704160742403 in words is "five trillion, seven hundred four billion, one hundred sixty million, seven hundred forty-two thousand, four hundred three".
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