Base | Representation |
---|---|
bin | 110101001100111011… |
… | …001000010010010001 |
3 | 12110110011000222021212 |
4 | 311030323020102101 |
5 | 1413443014044242 |
6 | 42124250025505 |
7 | 4061420465306 |
oct | 651473102221 |
9 | 173404028255 |
10 | 57125143697 |
11 | 22254721a66 |
12 | b0a3118295 |
13 | 5504c80b9b |
14 | 2a9cb450ad |
15 | 174517d782 |
hex | d4cec8491 |
57125143697 has 2 divisors, whose sum is σ = 57125143698. Its totient is φ = 57125143696.
The previous prime is 57125143651. The next prime is 57125143703. The reversal of 57125143697 is 79634152175.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 36950066176 + 20175077521 = 192224^2 + 142039^2 .
It is a cyclic number.
It is not a de Polignac number, because 57125143697 - 214 = 57125127313 is a prime.
It is not a weakly prime, because it can be changed into another prime (57125143597) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 28562571848 + 28562571849.
It is an arithmetic number, because the mean of its divisors is an integer number (28562571849).
Almost surely, 257125143697 is an apocalyptic number.
It is an amenable number.
57125143697 is a deficient number, since it is larger than the sum of its proper divisors (1).
57125143697 is an equidigital number, since it uses as much as digits as its factorization.
57125143697 is an evil number, because the sum of its binary digits is even.
The product of its digits is 1587600, while the sum is 50.
The spelling of 57125143697 in words is "fifty-seven billion, one hundred twenty-five million, one hundred forty-three thousand, six hundred ninety-seven".
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