Base | Representation |
---|---|
bin | 110101001100111100… |
… | …001100000111000111 |
3 | 12110110011120002101021 |
4 | 311030330030013013 |
5 | 1413443101442021 |
6 | 42124300012011 |
7 | 4061423033254 |
oct | 651474140707 |
9 | 173404502337 |
10 | 57125421511 |
11 | 222548a1764 |
12 | b0a3231007 |
13 | 550504a482 |
14 | 2a9cbb842b |
15 | 17451d5c41 |
hex | d4cf0c1c7 |
57125421511 has 4 divisors (see below), whose sum is σ = 57128536024. Its totient is φ = 57122307000.
The previous prime is 57125421503. The next prime is 57125421649. The reversal of 57125421511 is 11512452175.
57125421511 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 57125421511 - 23 = 57125421503 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (57125422511) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1529580 + ... + 1566481.
It is an arithmetic number, because the mean of its divisors is an integer number (14282134006).
Almost surely, 257125421511 is an apocalyptic number.
57125421511 is a deficient number, since it is larger than the sum of its proper divisors (3114513).
57125421511 is a wasteful number, since it uses less digits than its factorization.
57125421511 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3114512.
The product of its digits is 14000, while the sum is 34.
Adding to 57125421511 its reverse (11512452175), we get a palindrome (68637873686).
The spelling of 57125421511 in words is "fifty-seven billion, one hundred twenty-five million, four hundred twenty-one thousand, five hundred eleven".
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