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57140011603 is a prime number
BaseRepresentation
bin110101001101110011…
…110110001001010011
312110111012000100020001
4311031303312021103
51414010320332403
642125540430431
74061661041053
oct651563661123
9173435010201
1057140011603
1122262057494
12b0a80a8417
13550808836c
142aa0ad5563
151746618c1d
hexd4dcf6253

57140011603 has 2 divisors, whose sum is σ = 57140011604. Its totient is φ = 57140011602.

The previous prime is 57140011573. The next prime is 57140011619. The reversal of 57140011603 is 30611004175.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 57140011603 - 25 = 57140011571 is a prime.

It is not a weakly prime, because it can be changed into another prime (57140011633) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 28570005801 + 28570005802.

It is an arithmetic number, because the mean of its divisors is an integer number (28570005802).

Almost surely, 257140011603 is an apocalyptic number.

57140011603 is a deficient number, since it is larger than the sum of its proper divisors (1).

57140011603 is an equidigital number, since it uses as much as digits as its factorization.

57140011603 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2520, while the sum is 28.

Adding to 57140011603 its reverse (30611004175), we get a palindrome (87751015778).

The spelling of 57140011603 in words is "fifty-seven billion, one hundred forty million, eleven thousand, six hundred three".