Base | Representation |
---|---|
bin | 1010101001001110… |
… | …01111011001100011 |
3 | 112202020220201100111 |
4 | 11110213033121203 |
5 | 43200410241011 |
6 | 2343014232151 |
7 | 261416534566 |
oct | 52447173143 |
9 | 15666821314 |
10 | 5714540131 |
11 | 2472788643 |
12 | 1135955657 |
13 | 700bbc1c1 |
14 | 3c2d424dd |
15 | 236a4c121 |
hex | 1549cf663 |
5714540131 has 2 divisors, whose sum is σ = 5714540132. Its totient is φ = 5714540130.
The previous prime is 5714540071. The next prime is 5714540171. The reversal of 5714540131 is 1310454175.
5714540131 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 5714540131 - 29 = 5714539619 is a prime.
It is a super-2 number, since 2×57145401312 = 65311937817618994322, which contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 5714540093 and 5714540102.
It is not a weakly prime, because it can be changed into another prime (5714540171) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2857270065 + 2857270066.
It is an arithmetic number, because the mean of its divisors is an integer number (2857270066).
Almost surely, 25714540131 is an apocalyptic number.
5714540131 is a deficient number, since it is larger than the sum of its proper divisors (1).
5714540131 is an equidigital number, since it uses as much as digits as its factorization.
5714540131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 8400, while the sum is 31.
The square root of 5714540131 is about 75594.5773915034. The cubic root of 5714540131 is about 1787.8336025994.
The spelling of 5714540131 in words is "five billion, seven hundred fourteen million, five hundred forty thousand, one hundred thirty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.072 sec. • engine limits •