Base | Representation |
---|---|
bin | 110101010000100001… |
… | …111111000111111001 |
3 | 12110121100220121000111 |
4 | 311100201333013321 |
5 | 1414104012131213 |
6 | 42134251104321 |
7 | 4063054046665 |
oct | 652041770771 |
9 | 173540817014 |
10 | 57185661433 |
11 | 222858a691a |
12 | b0bb4420a1 |
13 | 551467c6b4 |
14 | 2aa6bb98a5 |
15 | 174a634a3d |
hex | d5087f1f9 |
57185661433 has 2 divisors, whose sum is σ = 57185661434. Its totient is φ = 57185661432.
The previous prime is 57185661347. The next prime is 57185661437. The reversal of 57185661433 is 33416658175.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 38616966144 + 18568695289 = 196512^2 + 136267^2 .
It is a cyclic number.
It is not a de Polignac number, because 57185661433 - 213 = 57185653241 is a prime.
It is a super-2 number, since 2×571856614332 (a number of 22 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (57185661437) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 28592830716 + 28592830717.
It is an arithmetic number, because the mean of its divisors is an integer number (28592830717).
Almost surely, 257185661433 is an apocalyptic number.
It is an amenable number.
57185661433 is a deficient number, since it is larger than the sum of its proper divisors (1).
57185661433 is an equidigital number, since it uses as much as digits as its factorization.
57185661433 is an evil number, because the sum of its binary digits is even.
The product of its digits is 1814400, while the sum is 49.
The spelling of 57185661433 in words is "fifty-seven billion, one hundred eighty-five million, six hundred sixty-one thousand, four hundred thirty-three".
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