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5724115 = 51144823
BaseRepresentation
bin10101110101011111010011
3101202211000021
4111311133103
52431132430
6322404311
766440245
oct25653723
911684007
105724115
11325a681
121b00697
131255567
14a90095
1578107a
hex5757d3

5724115 has 4 divisors (see below), whose sum is σ = 6868944. Its totient is φ = 4579288.

The previous prime is 5724113. The next prime is 5724127. The reversal of 5724115 is 5114275.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 5724115 - 21 = 5724113 is a prime.

It is a Duffinian number.

It is a plaindrome in base 13.

It is a self number, because there is not a number n which added to its sum of digits gives 5724115.

It is not an unprimeable number, because it can be changed into a prime (5724113) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 572407 + ... + 572416.

It is an arithmetic number, because the mean of its divisors is an integer number (1717236).

Almost surely, 25724115 is an apocalyptic number.

5724115 is a deficient number, since it is larger than the sum of its proper divisors (1144829).

5724115 is a wasteful number, since it uses less digits than its factorization.

5724115 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1144828.

The product of its digits is 1400, while the sum is 25.

The square root of 5724115 is about 2392.5122779204. The cubic root of 5724115 is about 178.8831566876.

The spelling of 5724115 in words is "five million, seven hundred twenty-four thousand, one hundred fifteen".

Divisors: 1 5 1144823 5724115