Base | Representation |
---|---|
bin | 11010000010100001001111… |
… | …11111101100110101100001 |
3 | 21111202010002201221221022201 |
4 | 31001100213333230311201 |
5 | 30001131341300003132 |
6 | 321441230505333201 |
7 | 15026661203520253 |
oct | 1501204777546541 |
9 | 244663081857281 |
10 | 57261175000417 |
11 | 17277367545913 |
12 | 6509723797201 |
13 | 25c492337816b |
14 | 101d654477cd3 |
15 | 6947642842e7 |
hex | 341427fecd61 |
57261175000417 has 2 divisors, whose sum is σ = 57261175000418. Its totient is φ = 57261175000416.
The previous prime is 57261175000307. The next prime is 57261175000427. The reversal of 57261175000417 is 71400057116275.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 47220109712721 + 10041065287696 = 6871689^2 + 3168764^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-57261175000417 is a prime.
It is not a weakly prime, because it can be changed into another prime (57261175000427) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 28630587500208 + 28630587500209.
It is an arithmetic number, because the mean of its divisors is an integer number (28630587500209).
Almost surely, 257261175000417 is an apocalyptic number.
It is an amenable number.
57261175000417 is a deficient number, since it is larger than the sum of its proper divisors (1).
57261175000417 is an equidigital number, since it uses as much as digits as its factorization.
57261175000417 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 411600, while the sum is 46.
The spelling of 57261175000417 in words is "fifty-seven trillion, two hundred sixty-one billion, one hundred seventy-five million, four hundred seventeen", and thus it is an aban number.
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