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57280254443 is a prime number
BaseRepresentation
bin110101010110001010…
…110101000111101011
312110211221220102020022
4311112022311013223
51414302221120233
642151510351055
74065313062236
oct652612650753
9173757812208
1057280254443
1122324234a65
12b12705b48b
13552b14c0a9
142ab55a041d
151753abc398
hexd562b51eb

57280254443 has 2 divisors, whose sum is σ = 57280254444. Its totient is φ = 57280254442.

The previous prime is 57280254413. The next prime is 57280254469. The reversal of 57280254443 is 34445208275.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 57280254443 - 230 = 56206512619 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 57280254394 and 57280254403.

It is not a weakly prime, because it can be changed into another prime (57280254413) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 28640127221 + 28640127222.

It is an arithmetic number, because the mean of its divisors is an integer number (28640127222).

Almost surely, 257280254443 is an apocalyptic number.

57280254443 is a deficient number, since it is larger than the sum of its proper divisors (1).

57280254443 is an equidigital number, since it uses as much as digits as its factorization.

57280254443 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1075200, while the sum is 44.

The spelling of 57280254443 in words is "fifty-seven billion, two hundred eighty million, two hundred fifty-four thousand, four hundred forty-three".