Base | Representation |
---|---|
bin | 101001101101011110101… |
… | …0001011111111011001111 |
3 | 202022001000001122121121211 |
4 | 1103122331101133323033 |
5 | 1222410442413311103 |
6 | 20105314250435251 |
7 | 1131112463523415 |
oct | 123327521377317 |
9 | 22261001577554 |
10 | 5732661853903 |
11 | 1910232191446 |
12 | 787040a32b27 |
13 | 327784214c7a |
14 | 15b6688392b5 |
15 | 9e1bde5036d |
hex | 536bd45fecf |
5732661853903 has 32 divisors (see below), whose sum is σ = 6051661304832. Its totient is φ = 5419770048000.
The previous prime is 5732661853847. The next prime is 5732661853921. The reversal of 5732661853903 is 3093581662375.
5732661853903 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 5732661853903 - 213 = 5732661845711 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (5732661853603) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 1736642353 + ... + 1736645653.
It is an arithmetic number, because the mean of its divisors is an integer number (189114415776).
Almost surely, 25732661853903 is an apocalyptic number.
5732661853903 is a deficient number, since it is larger than the sum of its proper divisors (318999450929).
5732661853903 is a wasteful number, since it uses less digits than its factorization.
5732661853903 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5095.
The product of its (nonzero) digits is 24494400, while the sum is 58.
The spelling of 5732661853903 in words is "five trillion, seven hundred thirty-two billion, six hundred sixty-one million, eight hundred fifty-three thousand, nine hundred three".
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