Base | Representation |
---|---|
bin | 110101011000111100… |
… | …010001010100011001 |
3 | 12110222012102121210201 |
4 | 311120330101110121 |
5 | 1414401123110213 |
6 | 42200251342201 |
7 | 4066416333403 |
oct | 653074212431 |
9 | 173865377721 |
10 | 57326769433 |
11 | 223485153aa |
12 | b13a751961 |
13 | 553798715b |
14 | 2abb82bb73 |
15 | 1757c096dd |
hex | d58f11519 |
57326769433 has 2 divisors, whose sum is σ = 57326769434. Its totient is φ = 57326769432.
The previous prime is 57326769413. The next prime is 57326769491. The reversal of 57326769433 is 33496762375.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 54537662089 + 2789107344 = 233533^2 + 52812^2 .
It is a cyclic number.
It is not a de Polignac number, because 57326769433 - 229 = 56789898521 is a prime.
It is not a weakly prime, because it can be changed into another prime (57326769413) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 28663384716 + 28663384717.
It is an arithmetic number, because the mean of its divisors is an integer number (28663384717).
Almost surely, 257326769433 is an apocalyptic number.
It is an amenable number.
57326769433 is a deficient number, since it is larger than the sum of its proper divisors (1).
57326769433 is an equidigital number, since it uses as much as digits as its factorization.
57326769433 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 17146080, while the sum is 55.
The spelling of 57326769433 in words is "fifty-seven billion, three hundred twenty-six million, seven hundred sixty-nine thousand, four hundred thirty-three".
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