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57405686473 is a prime number
BaseRepresentation
bin110101011101101001…
…010100001011001001
312111011200221000122001
4311131221110023021
51420031323431343
642212151031001
74101365166262
oct653551241311
9174150830561
1057405686473
11223890169a3
12b16106b461
13554b128625
142ac80d1969
15175eae744d
hexd5da542c9

57405686473 has 2 divisors, whose sum is σ = 57405686474. Its totient is φ = 57405686472.

The previous prime is 57405686467. The next prime is 57405686489. The reversal of 57405686473 is 37468650475.

57405686473 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 57335344704 + 70341769 = 239448^2 + 8387^2 .

It is a cyclic number.

It is not a de Polignac number, because 57405686473 - 217 = 57405555401 is a prime.

It is not a weakly prime, because it can be changed into another prime (57405686573) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 28702843236 + 28702843237.

It is an arithmetic number, because the mean of its divisors is an integer number (28702843237).

Almost surely, 257405686473 is an apocalyptic number.

It is an amenable number.

57405686473 is a deficient number, since it is larger than the sum of its proper divisors (1).

57405686473 is an equidigital number, since it uses as much as digits as its factorization.

57405686473 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 16934400, while the sum is 55.

The spelling of 57405686473 in words is "fifty-seven billion, four hundred five million, six hundred eighty-six thousand, four hundred seventy-three".