Base | Representation |
---|---|
bin | 110101011111001011… |
… | …011010011010010011 |
3 | 12111020111022111212211 |
4 | 311133023122122103 |
5 | 1420104414332011 |
6 | 42214510132551 |
7 | 4102126602115 |
oct | 653713323223 |
9 | 174214274784 |
10 | 57431402131 |
11 | 223a1590504 |
12 | b1697b1157 |
13 | 55535604ac |
14 | 2acb6a73b5 |
15 | 1761ec6b21 |
hex | d5f2da693 |
57431402131 has 2 divisors, whose sum is σ = 57431402132. Its totient is φ = 57431402130.
The previous prime is 57431402101. The next prime is 57431402143. The reversal of 57431402131 is 13120413475.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 57431402131 - 29 = 57431401619 is a prime.
It is a super-2 number, since 2×574314021312 (a number of 22 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 57431402093 and 57431402102.
It is not a weakly prime, because it can be changed into another prime (57431402101) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 28715701065 + 28715701066.
It is an arithmetic number, because the mean of its divisors is an integer number (28715701066).
Almost surely, 257431402131 is an apocalyptic number.
57431402131 is a deficient number, since it is larger than the sum of its proper divisors (1).
57431402131 is an equidigital number, since it uses as much as digits as its factorization.
57431402131 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 10080, while the sum is 31.
The spelling of 57431402131 in words is "fifty-seven billion, four hundred thirty-one million, four hundred two thousand, one hundred thirty-one".
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