Base | Representation |
---|---|
bin | 101001110101100110101… |
… | …0001010110010001000111 |
3 | 202100201001001122022121211 |
4 | 1103223031101112101013 |
5 | 1223202211142301413 |
6 | 20121321503352251 |
7 | 1132301042400046 |
oct | 123531521262107 |
9 | 22321031568554 |
10 | 5750110118983 |
11 | 191767629122a |
12 | 78a4b02b2687 |
13 | 329305048489 |
14 | 15c441c8455d |
15 | 9e890b7183d |
hex | 53acd456447 |
5750110118983 has 8 divisors (see below), whose sum is σ = 6061886853120. Its totient is φ = 5446226466840.
The previous prime is 5750110118981. The next prime is 5750110119001. The reversal of 5750110118983 is 3898110110575.
5750110118983 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 5750110118983 - 21 = 5750110118981 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (5750110118981) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1973269003 + ... + 1973271916.
It is an arithmetic number, because the mean of its divisors is an integer number (757735856640).
Almost surely, 25750110118983 is an apocalyptic number.
5750110118983 is a deficient number, since it is larger than the sum of its proper divisors (311776734137).
5750110118983 is a wasteful number, since it uses less digits than its factorization.
5750110118983 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 3946540997.
The product of its (nonzero) digits is 302400, while the sum is 49.
The spelling of 5750110118983 in words is "five trillion, seven hundred fifty billion, one hundred ten million, one hundred eighteen thousand, nine hundred eighty-three".
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