Base | Representation |
---|---|
bin | 11010001001101001101111… |
… | …10000100110000111010111 |
3 | 21112121112200121201120000220 |
4 | 31010310313300212013113 |
5 | 30014140301132041210 |
6 | 322150001401205423 |
7 | 15053455356040452 |
oct | 1504646760460727 |
9 | 245545617646026 |
10 | 57506252612055 |
11 | 173612a0461905 |
12 | 654911b790873 |
13 | 2611a7c6b0700 |
14 | 102b46322c499 |
15 | 69ad09d77c70 |
hex | 344d37c261d7 |
57506252612055 has 48 divisors (see below), whose sum is σ = 99636988895136. Its totient is φ = 28309391185920.
The previous prime is 57506252611993. The next prime is 57506252612089. The reversal of 57506252612055 is 55021625260575.
It is not a de Polignac number, because 57506252612055 - 217 = 57506252480983 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 57506252611989 and 57506252612007.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 52492579 + ... + 53576891.
It is an arithmetic number, because the mean of its divisors is an integer number (2075770601982).
Almost surely, 257506252612055 is an apocalyptic number.
57506252612055 is a deficient number, since it is larger than the sum of its proper divisors (42130736283081).
57506252612055 is a wasteful number, since it uses less digits than its factorization.
57506252612055 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1105268 (or 1105255 counting only the distinct ones).
The product of its (nonzero) digits is 6300000, while the sum is 51.
The spelling of 57506252612055 in words is "fifty-seven trillion, five hundred six billion, two hundred fifty-two million, six hundred twelve thousand, fifty-five".
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