Base | Representation |
---|---|
bin | 110101101001111110… |
… | …001101100011010001 |
3 | 12111201010001210001112 |
4 | 311221332031203101 |
5 | 1420442244202321 |
6 | 42244455343105 |
7 | 4106456043644 |
oct | 655176154321 |
9 | 174633053045 |
10 | 57612490961 |
11 | 224848271a3 |
12 | b1ba381a95 |
13 | 5581c25b4c |
14 | 2b07765a5b |
15 | 1772d47a5b |
hex | d69f8d8d1 |
57612490961 has 2 divisors, whose sum is σ = 57612490962. Its totient is φ = 57612490960.
The previous prime is 57612490933. The next prime is 57612490979. The reversal of 57612490961 is 16909421675.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 44328775936 + 13283715025 = 210544^2 + 115255^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-57612490961 is a prime.
It is a super-2 number, since 2×576124909612 (a number of 22 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (57612490931) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 28806245480 + 28806245481.
It is an arithmetic number, because the mean of its divisors is an integer number (28806245481).
Almost surely, 257612490961 is an apocalyptic number.
It is an amenable number.
57612490961 is a deficient number, since it is larger than the sum of its proper divisors (1).
57612490961 is an equidigital number, since it uses as much as digits as its factorization.
57612490961 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 816480, while the sum is 50.
The spelling of 57612490961 in words is "fifty-seven billion, six hundred twelve million, four hundred ninety thousand, nine hundred sixty-one".
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