Base | Representation |
---|---|
bin | 110101101100110100… |
… | …101010001011000011 |
3 | 12111211110001122222021 |
4 | 311230310222023003 |
5 | 1421042020142103 |
6 | 42253324422311 |
7 | 4110606422362 |
oct | 655464521303 |
9 | 174743048867 |
10 | 57660318403 |
11 | 224a9823706 |
12 | b2123a7997 |
13 | 558bb003cc |
14 | 2b0dc557d9 |
15 | 1777143bbd |
hex | d6cd2a2c3 |
57660318403 has 2 divisors, whose sum is σ = 57660318404. Its totient is φ = 57660318402.
The previous prime is 57660318367. The next prime is 57660318407. The reversal of 57660318403 is 30481306675.
57660318403 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-57660318403 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 57660318403.
It is not a weakly prime, because it can be changed into another prime (57660318407) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 28830159201 + 28830159202.
It is an arithmetic number, because the mean of its divisors is an integer number (28830159202).
Almost surely, 257660318403 is an apocalyptic number.
57660318403 is a deficient number, since it is larger than the sum of its proper divisors (1).
57660318403 is an equidigital number, since it uses as much as digits as its factorization.
57660318403 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 362880, while the sum is 43.
The spelling of 57660318403 in words is "fifty-seven billion, six hundred sixty million, three hundred eighteen thousand, four hundred three".
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