Base | Representation |
---|---|
bin | 11010001111011110001100… |
… | …11101000100101111011001 |
3 | 21120022122211100111001201121 |
4 | 31013233012131010233121 |
5 | 30030424312033211441 |
6 | 322421511432045241 |
7 | 15104064543313513 |
oct | 1507570635045731 |
9 | 246278740431647 |
10 | 57706215132121 |
11 | 17429083053856 |
12 | 657ba26833821 |
13 | 26278990090ba |
14 | 1036dd2354bb3 |
15 | 6a110ed96dd1 |
hex | 347bc6744bd9 |
57706215132121 has 2 divisors, whose sum is σ = 57706215132122. Its totient is φ = 57706215132120.
The previous prime is 57706215132113. The next prime is 57706215132127. The reversal of 57706215132121 is 12123151260775.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 35312545614096 + 22393669518025 = 5942436^2 + 4732195^2 .
It is a cyclic number.
It is not a de Polignac number, because 57706215132121 - 23 = 57706215132113 is a prime.
It is not a weakly prime, because it can be changed into another prime (57706215132127) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 28853107566060 + 28853107566061.
It is an arithmetic number, because the mean of its divisors is an integer number (28853107566061).
Almost surely, 257706215132121 is an apocalyptic number.
It is an amenable number.
57706215132121 is a deficient number, since it is larger than the sum of its proper divisors (1).
57706215132121 is an equidigital number, since it uses as much as digits as its factorization.
57706215132121 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 176400, while the sum is 43.
Adding to 57706215132121 its reverse (12123151260775), we get a palindrome (69829366392896).
The spelling of 57706215132121 in words is "fifty-seven trillion, seven hundred six billion, two hundred fifteen million, one hundred thirty-two thousand, one hundred twenty-one".
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