Base | Representation |
---|---|
bin | 101010000010001010000… |
… | …1011111101001000101001 |
3 | 202110021121220211111111011 |
4 | 1110010110023331020221 |
5 | 1224122414320111213 |
6 | 20141541004503521 |
7 | 1134244113104455 |
oct | 124042413751051 |
9 | 22407556744434 |
10 | 5777069691433 |
11 | 1928050262017 |
12 | 793774b4aba1 |
13 | 32ba10542a01 |
14 | 15d87c5a1665 |
15 | a041c8bd03d |
hex | 541142fd229 |
5777069691433 has 2 divisors, whose sum is σ = 5777069691434. Its totient is φ = 5777069691432.
The previous prime is 5777069691347. The next prime is 5777069691473. The reversal of 5777069691433 is 3341969607775.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 4878921133584 + 898148557849 = 2208828^2 + 947707^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-5777069691433 is a prime.
It is not a weakly prime, because it can be changed into another prime (5777069691473) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2888534845716 + 2888534845717.
It is an arithmetic number, because the mean of its divisors is an integer number (2888534845717).
Almost surely, 25777069691433 is an apocalyptic number.
It is an amenable number.
5777069691433 is a deficient number, since it is larger than the sum of its proper divisors (1).
5777069691433 is an equidigital number, since it uses as much as digits as its factorization.
5777069691433 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 180033840, while the sum is 67.
The spelling of 5777069691433 in words is "five trillion, seven hundred seventy-seven billion, sixty-nine million, six hundred ninety-one thousand, four hundred thirty-three".
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