Base | Representation |
---|---|
bin | 1010110001010100… |
… | …11111010100100011 |
3 | 112220222210110122111 |
4 | 11120222133110203 |
5 | 43320310010033 |
6 | 2353443020151 |
7 | 263203305313 |
oct | 53052372443 |
9 | 15828713574 |
10 | 5782500643 |
11 | 24a8086357 |
12 | 115466a657 |
13 | 711cc561a |
14 | 3cbd93443 |
15 | 23c9c37cd |
hex | 158a9f523 |
5782500643 has 2 divisors, whose sum is σ = 5782500644. Its totient is φ = 5782500642.
The previous prime is 5782500629. The next prime is 5782500671. The reversal of 5782500643 is 3460052875.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 5782500643 - 29 = 5782500131 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 5782500596 and 5782500605.
It is not a weakly prime, because it can be changed into another prime (5782504643) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2891250321 + 2891250322.
It is an arithmetic number, because the mean of its divisors is an integer number (2891250322).
Almost surely, 25782500643 is an apocalyptic number.
5782500643 is a deficient number, since it is larger than the sum of its proper divisors (1).
5782500643 is an equidigital number, since it uses as much as digits as its factorization.
5782500643 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 201600, while the sum is 40.
The square root of 5782500643 is about 76042.7553617042. The cubic root of 5782500643 is about 1794.8929975554.
The spelling of 5782500643 in words is "five billion, seven hundred eighty-two million, five hundred thousand, six hundred forty-three".
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