Base | Representation |
---|---|
bin | 101010000101000111100… |
… | …0000001000011111111001 |
3 | 202110220000211202121101221 |
4 | 1110022033000020133321 |
5 | 1224223423320011423 |
6 | 20144511400312041 |
7 | 1134560444503102 |
oct | 124121700103771 |
9 | 22426024677357 |
10 | 5783425157113 |
11 | 192a81180049a |
12 | 794a49472621 |
13 | 32c4b41596a6 |
14 | 15dcc26a13a9 |
15 | a069081de5d |
hex | 5428f0087f9 |
5783425157113 has 2 divisors, whose sum is σ = 5783425157114. Its totient is φ = 5783425157112.
The previous prime is 5783425156967. The next prime is 5783425157177. The reversal of 5783425157113 is 3117515243875.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 4448690892864 + 1334734264249 = 2109192^2 + 1155307^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-5783425157113 is a prime.
It is not a weakly prime, because it can be changed into another prime (5783425157513) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2891712578556 + 2891712578557.
It is an arithmetic number, because the mean of its divisors is an integer number (2891712578557).
Almost surely, 25783425157113 is an apocalyptic number.
It is an amenable number.
5783425157113 is a deficient number, since it is larger than the sum of its proper divisors (1).
5783425157113 is an equidigital number, since it uses as much as digits as its factorization.
5783425157113 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 3528000, while the sum is 52.
The spelling of 5783425157113 in words is "five trillion, seven hundred eighty-three billion, four hundred twenty-five million, one hundred fifty-seven thousand, one hundred thirteen".
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