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57876453473 is a prime number
BaseRepresentation
bin110101111001101101…
…001001100001100001
312112101111202110112212
4311321231021201201
51422012333002343
642331005131505
74116142510646
oct657155114141
9175344673485
1057876453473
11225aa827133
12b272859b95
1355c4816897
142b30837dcd
15178b0d8c18
hexd79b49861

57876453473 has 2 divisors, whose sum is σ = 57876453474. Its totient is φ = 57876453472.

The previous prime is 57876453409. The next prime is 57876453487. The reversal of 57876453473 is 37435467875.

57876453473 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 57808027489 + 68425984 = 240433^2 + 8272^2 .

It is a cyclic number.

It is not a de Polignac number, because 57876453473 - 26 = 57876453409 is a prime.

It is a super-2 number, since 2×578764534732 (a number of 22 digits) contains 22 as substring.

It is a Sophie Germain prime.

It is a Curzon number.

It is not a weakly prime, because it can be changed into another prime (57876455473) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 28938226736 + 28938226737.

It is an arithmetic number, because the mean of its divisors is an integer number (28938226737).

Almost surely, 257876453473 is an apocalyptic number.

It is an amenable number.

57876453473 is a deficient number, since it is larger than the sum of its proper divisors (1).

57876453473 is an equidigital number, since it uses as much as digits as its factorization.

57876453473 is an evil number, because the sum of its binary digits is even.

The product of its digits is 59270400, while the sum is 59.

The spelling of 57876453473 in words is "fifty-seven billion, eight hundred seventy-six million, four hundred fifty-three thousand, four hundred seventy-three".