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57894433 is a prime number
BaseRepresentation
bin1101110011011…
…0011000100001
311000221100020021
43130312120201
5104310110213
65424513441
71302044302
oct334663041
9130840207
1057894433
112a752a43
121747b881
13bcc077c
1479907a9
155138d8d
hex3736621

57894433 has 2 divisors, whose sum is σ = 57894434. Its totient is φ = 57894432.

The previous prime is 57894413. The next prime is 57894491. The reversal of 57894433 is 33449875.

57894433 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 57881664 + 12769 = 7608^2 + 113^2 .

It is a cyclic number.

It is not a de Polignac number, because 57894433 - 217 = 57763361 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 57894433.

It is not a weakly prime, because it can be changed into another prime (57894413) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 28947216 + 28947217.

It is an arithmetic number, because the mean of its divisors is an integer number (28947217).

Almost surely, 257894433 is an apocalyptic number.

It is an amenable number.

57894433 is a deficient number, since it is larger than the sum of its proper divisors (1).

57894433 is an equidigital number, since it uses as much as digits as its factorization.

57894433 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 362880, while the sum is 43.

The square root of 57894433 is about 7608.8391361626. The cubic root of 57894433 is about 386.8526726788.

The spelling of 57894433 in words is "fifty-seven million, eight hundred ninety-four thousand, four hundred thirty-three".