Base | Representation |
---|---|
bin | 110110000111110100… |
… | …001111111100010001 |
3 | 12120000000020012221221 |
4 | 312013310033330101 |
5 | 1423003434231133 |
6 | 42410303245041 |
7 | 4125046004542 |
oct | 660764177421 |
9 | 176000205857 |
10 | 58113195793 |
11 | 22711425144 |
12 | b319ba9781 |
13 | 56318969b3 |
14 | 2b540624c9 |
15 | 17a1c9ea2d |
hex | d87d0ff11 |
58113195793 has 2 divisors, whose sum is σ = 58113195794. Its totient is φ = 58113195792.
The previous prime is 58113195739. The next prime is 58113195809. The reversal of 58113195793 is 39759131185.
Together with previous prime (58113195739) it forms an Ormiston pair, because they use the same digits, order apart.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 43561116369 + 14552079424 = 208713^2 + 120632^2 .
It is a cyclic number.
It is not a de Polignac number, because 58113195793 - 29 = 58113195281 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 58113195793.
It is not a weakly prime, because it can be changed into another prime (58113195733) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 29056597896 + 29056597897.
It is an arithmetic number, because the mean of its divisors is an integer number (29056597897).
Almost surely, 258113195793 is an apocalyptic number.
It is an amenable number.
58113195793 is a deficient number, since it is larger than the sum of its proper divisors (1).
58113195793 is an equidigital number, since it uses as much as digits as its factorization.
58113195793 is an evil number, because the sum of its binary digits is even.
The product of its digits is 1020600, while the sum is 52.
The spelling of 58113195793 in words is "fifty-eight billion, one hundred thirteen million, one hundred ninety-five thousand, seven hundred ninety-three".
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