Base | Representation |
---|---|
bin | 110110001000111101… |
… | …111000001001101001 |
3 | 12120001100112211020111 |
4 | 312020331320021221 |
5 | 1423023404401001 |
6 | 42412233054321 |
7 | 4125402033355 |
oct | 661075701151 |
9 | 176040484214 |
10 | 58132497001 |
11 | 22721308457 |
12 | b3245573a1 |
13 | 5635894027 |
14 | 2b56848465 |
15 | 17a3813851 |
hex | d88f78269 |
58132497001 has 2 divisors, whose sum is σ = 58132497002. Its totient is φ = 58132497000.
The previous prime is 58132496927. The next prime is 58132497013. The reversal of 58132497001 is 10079423185.
58132497001 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 55612958976 + 2519538025 = 235824^2 + 50195^2 .
It is a cyclic number.
It is not a de Polignac number, because 58132497001 - 213 = 58132488809 is a prime.
It is not a weakly prime, because it can be changed into another prime (58132497601) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 29066248500 + 29066248501.
It is an arithmetic number, because the mean of its divisors is an integer number (29066248501).
Almost surely, 258132497001 is an apocalyptic number.
It is an amenable number.
58132497001 is a deficient number, since it is larger than the sum of its proper divisors (1).
58132497001 is an equidigital number, since it uses as much as digits as its factorization.
58132497001 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 60480, while the sum is 40.
The spelling of 58132497001 in words is "fifty-eight billion, one hundred thirty-two million, four hundred ninety-seven thousand, one".
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