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58803312604217 is a prime number
BaseRepresentation
bin11010101111011001101101…
…00011110011010000111001
321201012112121221221010200212
431113230312203303100321
530201413141011313332
6325021511402240505
715246253622051546
oct1527546643632071
9251175557833625
1058803312604217
1117811387a69655
1267185864b6135
1326a7189669b2c
14107414a149bcd
156be920b098b2
hex357b368f3439

58803312604217 has 2 divisors, whose sum is σ = 58803312604218. Its totient is φ = 58803312604216.

The previous prime is 58803312604199. The next prime is 58803312604261. The reversal of 58803312604217 is 71240621330885.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 57930304550416 + 873008053801 = 7611196^2 + 934349^2 .

It is a cyclic number.

It is not a de Polignac number, because 58803312604217 - 210 = 58803312603193 is a prime.

It is not a weakly prime, because it can be changed into another prime (58803312604297) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 29401656302108 + 29401656302109.

It is an arithmetic number, because the mean of its divisors is an integer number (29401656302109).

Almost surely, 258803312604217 is an apocalyptic number.

It is an amenable number.

58803312604217 is a deficient number, since it is larger than the sum of its proper divisors (1).

58803312604217 is an equidigital number, since it uses as much as digits as its factorization.

58803312604217 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1935360, while the sum is 50.

The spelling of 58803312604217 in words is "fifty-eight trillion, eight hundred three billion, three hundred twelve million, six hundred four thousand, two hundred seventeen".