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58805113 is a prime number
BaseRepresentation
bin1110000001010…
…0101101111001
311002122121110011
43200110231321
5110023230423
65500221521
71312556323
oct340245571
9132577404
1058805113
1130215174
121783a8a1
13c24c133
147b4a613
155268b0d
hex3814b79

58805113 has 2 divisors, whose sum is σ = 58805114. Its totient is φ = 58805112.

The previous prime is 58805101. The next prime is 58805119. The reversal of 58805113 is 31150885.

58805113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 58798224 + 6889 = 7668^2 + 83^2 .

It is a cyclic number.

It is not a de Polignac number, because 58805113 - 225 = 25250681 is a prime.

It is not a weakly prime, because it can be changed into another prime (58805119) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 29402556 + 29402557.

It is an arithmetic number, because the mean of its divisors is an integer number (29402557).

Almost surely, 258805113 is an apocalyptic number.

It is an amenable number.

58805113 is a deficient number, since it is larger than the sum of its proper divisors (1).

58805113 is an equidigital number, since it uses as much as digits as its factorization.

58805113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 4800, while the sum is 31.

The square root of 58805113 is about 7668.4491913294. The cubic root of 58805113 is about 388.8705278618.

Adding to 58805113 its reverse (31150885), we get a palindrome (89955998).

The spelling of 58805113 in words is "fifty-eight million, eight hundred five thousand, one hundred thirteen".