Base | Representation |
---|---|
bin | 110111000011001110… |
… | …001010000101101011 |
3 | 12122120110121011022211 |
4 | 313003032022011223 |
5 | 1432024104441212 |
6 | 43053225025551 |
7 | 4161540243454 |
oct | 670316120553 |
9 | 178513534284 |
10 | 59109843307 |
11 | 23082a69179 |
12 | b5579252b7 |
13 | 57601cbc58 |
14 | 2c0a57a12b |
15 | 180e51c9a7 |
hex | dc338a16b |
59109843307 has 2 divisors, whose sum is σ = 59109843308. Its totient is φ = 59109843306.
The previous prime is 59109843271. The next prime is 59109843323. The reversal of 59109843307 is 70334890195.
59109843307 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 59109843307 - 27 = 59109843179 is a prime.
It is not a weakly prime, because it can be changed into another prime (59109843337) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 29554921653 + 29554921654.
It is an arithmetic number, because the mean of its divisors is an integer number (29554921654).
Almost surely, 259109843307 is an apocalyptic number.
59109843307 is a deficient number, since it is larger than the sum of its proper divisors (1).
59109843307 is an equidigital number, since it uses as much as digits as its factorization.
59109843307 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 816480, while the sum is 49.
The spelling of 59109843307 in words is "fifty-nine billion, one hundred nine million, eight hundred forty-three thousand, three hundred seven".
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