Base | Representation |
---|---|
bin | 110111000011001110… |
… | …100101110101011001 |
3 | 12122120110210221012221 |
4 | 313003032211311121 |
5 | 1432024122110303 |
6 | 43053231304041 |
7 | 4161541226005 |
oct | 670316456531 |
9 | 178513727187 |
10 | 59109956953 |
11 | 230830365a3 |
12 | b55797b021 |
13 | 576023b8b8 |
14 | 2c0a5a9705 |
15 | 180e5414bd |
hex | dc33a5d59 |
59109956953 has 2 divisors, whose sum is σ = 59109956954. Its totient is φ = 59109956952.
The previous prime is 59109956929. The next prime is 59109956993. The reversal of 59109956953 is 35965990195.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 57127214169 + 1982742784 = 239013^2 + 44528^2 .
It is a cyclic number.
It is not a de Polignac number, because 59109956953 - 217 = 59109825881 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 59109956891 and 59109956900.
It is not a weakly prime, because it can be changed into another prime (59109956993) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 29554978476 + 29554978477.
It is an arithmetic number, because the mean of its divisors is an integer number (29554978477).
Almost surely, 259109956953 is an apocalyptic number.
It is an amenable number.
59109956953 is a deficient number, since it is larger than the sum of its proper divisors (1).
59109956953 is an equidigital number, since it uses as much as digits as its factorization.
59109956953 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 14762250, while the sum is 61.
The spelling of 59109956953 in words is "fifty-nine billion, one hundred nine million, nine hundred fifty-six thousand, nine hundred fifty-three".
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