Base | Representation |
---|---|
bin | 101011000001000010001… |
… | …0011000011100111011001 |
3 | 202221012011000222220110021 |
4 | 1112002010103003213121 |
5 | 1233330432203243403 |
6 | 20323551224550441 |
7 | 1150064133556243 |
oct | 126020423034731 |
9 | 22835130886407 |
10 | 5912094587353 |
11 | 197a33a2a2899 |
12 | 7b5978622421 |
13 | 33b67b481b26 |
14 | 16620b16d093 |
15 | a3bc19548bd |
hex | 560844c39d9 |
5912094587353 has 2 divisors, whose sum is σ = 5912094587354. Its totient is φ = 5912094587352.
The previous prime is 5912094587249. The next prime is 5912094587369. The reversal of 5912094587353 is 3537854902195.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 5910602155929 + 1492431424 = 2431173^2 + 38632^2 .
It is a cyclic number.
It is not a de Polignac number, because 5912094587353 - 213 = 5912094579161 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 5912094587291 and 5912094587300.
It is not a weakly prime, because it can be changed into another prime (5912094587653) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2956047293676 + 2956047293677.
It is an arithmetic number, because the mean of its divisors is an integer number (2956047293677).
Almost surely, 25912094587353 is an apocalyptic number.
It is an amenable number.
5912094587353 is a deficient number, since it is larger than the sum of its proper divisors (1).
5912094587353 is an equidigital number, since it uses as much as digits as its factorization.
5912094587353 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 40824000, while the sum is 61.
The spelling of 5912094587353 in words is "five trillion, nine hundred twelve billion, ninety-four million, five hundred eighty-seven thousand, three hundred fifty-three".
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