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5920114873 is a prime number
BaseRepresentation
bin1011000001101110…
…11100100010111001
3120021120201222212211
411200313130202321
544111022133443
62415240335121
7266464101061
oct54067344271
916246658784
105920114873
112568828a22
1211927744a1
13734678a6a
144023763a1
15249b0819d
hex160ddc8b9

5920114873 has 2 divisors, whose sum is σ = 5920114874. Its totient is φ = 5920114872.

The previous prime is 5920114859. The next prime is 5920114883. The reversal of 5920114873 is 3784110295.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 5624550009 + 295564864 = 74997^2 + 17192^2 .

It is a cyclic number.

It is not a de Polignac number, because 5920114873 - 213 = 5920106681 is a prime.

It is a super-2 number, since 2×59201148732 = 70095520219031612258, which contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (5920114883) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2960057436 + 2960057437.

It is an arithmetic number, because the mean of its divisors is an integer number (2960057437).

Almost surely, 25920114873 is an apocalyptic number.

It is an amenable number.

5920114873 is a deficient number, since it is larger than the sum of its proper divisors (1).

5920114873 is an equidigital number, since it uses as much as digits as its factorization.

5920114873 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 60480, while the sum is 40.

The square root of 5920114873 is about 76942.2827384267. The cubic root of 5920114873 is about 1809.0200400268.

The spelling of 5920114873 in words is "five billion, nine hundred twenty million, one hundred fourteen thousand, eight hundred seventy-three".