Base | Representation |
---|---|
bin | 1011000100001101… |
… | …11001011101111001 |
3 | 120100000221011022022 |
4 | 11202012321131321 |
5 | 44131340131323 |
6 | 2421303004225 |
7 | 300136115456 |
oct | 54206713571 |
9 | 16300834268 |
10 | 5940942713 |
11 | 2579564212 |
12 | 1199739675 |
13 | 738a8bc24 |
14 | 40503882d |
15 | 24b86e4c8 |
hex | 1621b9779 |
5940942713 has 2 divisors, whose sum is σ = 5940942714. Its totient is φ = 5940942712.
The previous prime is 5940942701. The next prime is 5940942731. The reversal of 5940942713 is 3172490495.
Together with next prime (5940942731) it forms an Ormiston pair, because they use the same digits, order apart.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 5904846649 + 36096064 = 76843^2 + 6008^2 .
It is a cyclic number.
It is not a de Polignac number, because 5940942713 - 210 = 5940941689 is a prime.
It is not a weakly prime, because it can be changed into another prime (5940942773) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2970471356 + 2970471357.
It is an arithmetic number, because the mean of its divisors is an integer number (2970471357).
Almost surely, 25940942713 is an apocalyptic number.
It is an amenable number.
5940942713 is a deficient number, since it is larger than the sum of its proper divisors (1).
5940942713 is an equidigital number, since it uses as much as digits as its factorization.
5940942713 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 272160, while the sum is 44.
The square root of 5940942713 is about 77077.5110716479. The cubic root of 5940942713 is about 1811.1390237148.
The spelling of 5940942713 in words is "five billion, nine hundred forty million, nine hundred forty-two thousand, seven hundred thirteen".
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