5942413000114 has 4 divisors (see below), whose sum is σ = 8913619500174. Its totient is φ = 2971206500056.

The previous prime is 5942413000091. The next prime is 5942413000123. The reversal of 5942413000114 is 4110003142495.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 4862320474489 + 1080092525625 = 2205067^2 + 1039275^2 .

It is a super-3 number, since 3×5942413000114³ (a number of 39 digits) contains 333 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 5942413000114.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1485603250027 + ... + 1485603250030.

Almost surely, 2^{5942413000114} is an apocalyptic number.

5942413000114 is a deficient number, since it is larger than the sum of its proper divisors (2971206500060).

5942413000114 is a wasteful number, since it uses less digits than its factorization.

5942413000114 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2971206500059.

The product of its (nonzero) digits is 17280, while the sum is 34.

The spelling of 5942413000114 in words is "five trillion, nine hundred forty-two billion, four hundred thirteen million, one hundred fourteen", and thus it is an aban number.