Base | Representation |
---|---|
bin | 1011000101111001… |
… | …01011000011001001 |
3 | 120101000110100101001 |
4 | 11202330223003021 |
5 | 44143442230213 |
6 | 2422525055001 |
7 | 300400000000 |
oct | 54274530311 |
9 | 16330410331 |
10 | 5955039433 |
11 | 25865122a2 |
12 | 11a23b7461 |
13 | 73b986395 |
14 | 406c67c37 |
15 | 24cc061dd |
hex | 162f2b0c9 |
5955039433 has 18 divisors (see below), whose sum is σ = 6954271434. Its totient is φ = 5099378256.
The previous prime is 5955039403. The next prime is 5955039439. The reversal of 5955039433 is 3349305595.
It is a happy number.
It can be written as a sum of positive squares in only one way, i.e., 5903156224 + 51883209 = 76832^2 + 7203^2 .
It is a de Polignac number, because none of the positive numbers 2k-5955039433 is a prime.
It is a super-2 number, since 2×59550394332 = 70924989297169922978, which contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (5955039439) by changing a digit.
It is a polite number, since it can be written in 17 ways as a sum of consecutive naturals, for example, 5764285 + ... + 5765317.
It is an arithmetic number, because the mean of its divisors is an integer number (386348413).
Almost surely, 25955039433 is an apocalyptic number.
It is an amenable number.
5955039433 is a deficient number, since it is larger than the sum of its proper divisors (999232001).
5955039433 is an frugal number, since it uses more digits than its factorization.
5955039433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1089 (or 1040 counting only the distinct ones).
The product of its (nonzero) digits is 1093500, while the sum is 46.
The square root of 5955039433 is about 77168.9019813033. The cubic root of 5955039433 is about 1812.5703876145.
The spelling of 5955039433 in words is "five billion, nine hundred fifty-five million, thirty-nine thousand, four hundred thirty-three".
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