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59913403934497 is a prime number
BaseRepresentation
bin11011001111101101011010…
…01010001010011100100001
321212010122222010121121010221
431213312231022022130201
530323110122401400442
6331231500544123041
715422413000504231
oct1547665512123441
9255118863547127
1059913403934497
11180aa14a644423
126877751906481
132757a6b02bb49
1410b1b7794bcc1
156dd7424a9467
hex367dad28a721

59913403934497 has 2 divisors, whose sum is σ = 59913403934498. Its totient is φ = 59913403934496.

The previous prime is 59913403934491. The next prime is 59913403934513. The reversal of 59913403934497 is 79443930431995.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 56755671380496 + 3157732554001 = 7533636^2 + 1777001^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-59913403934497 is a prime.

It is not a weakly prime, because it can be changed into another prime (59913403934491) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 29956701967248 + 29956701967249.

It is an arithmetic number, because the mean of its divisors is an integer number (29956701967249).

Almost surely, 259913403934497 is an apocalyptic number.

It is an amenable number.

59913403934497 is a deficient number, since it is larger than the sum of its proper divisors (1).

59913403934497 is an equidigital number, since it uses as much as digits as its factorization.

59913403934497 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 396809280, while the sum is 70.

The spelling of 59913403934497 in words is "fifty-nine trillion, nine hundred thirteen billion, four hundred three million, nine hundred thirty-four thousand, four hundred ninety-seven".