601213433 has 2 divisors, whose sum is σ = 601213434. Its totient is φ = 601213432.

The previous prime is 601213429. The next prime is 601213451. The reversal of 601213433 is 334312106.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 405297424 + 195916009 = 20132^2 + 13997^2 .

It is a cyclic number.

It is not a de Polignac number, because 601213433 - 2² = 601213429 is a prime.

It is a super-2 number, since 2×601213433² = 722915184039290978, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 601213399 and 601213408.

It is not a weakly prime, because it can be changed into another prime (601213453) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 300606716 + 300606717.

It is an arithmetic number, because the mean of its divisors is an integer number (300606717).

Almost surely, 2^601213433 is an apocalyptic number.

It is an amenable number.

601213433 is a deficient number, since it is larger than the sum of its proper divisors (1).

601213433 is an equidigital number, since it uses as much as digits as its factorization.

601213433 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1296, while the sum is 23.

The square root of 601213433 is about 24519.6540146879. The cubic root of 601213433 is about 844.0008652275. Note that the first 3 decimals are identical.

Adding to 601213433 its reverse (334312106), we get a palindrome (935525539).

The spelling of 601213433 in words is "six hundred one million, two hundred thirteen thousand, four hundred thirty-three".