Base | Representation |
---|---|
bin | 111000000000011110… |
… | …101000001100101001 |
3 | 12202020002110010211122 |
4 | 320000132220030221 |
5 | 1441130204233423 |
6 | 43343220505025 |
7 | 4226156630444 |
oct | 700036501451 |
9 | 182202403748 |
10 | 60137571113 |
11 | 235601002a4 |
12 | b7a3b4b175 |
13 | 58950c6b09 |
14 | 2ca6c6465b |
15 | 186e8798c8 |
hex | e007a8329 |
60137571113 has 2 divisors, whose sum is σ = 60137571114. Its totient is φ = 60137571112.
The previous prime is 60137571079. The next prime is 60137571133. The reversal of 60137571113 is 31117573106.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 36797981584 + 23339589529 = 191828^2 + 152773^2 .
It is a cyclic number.
It is not a de Polignac number, because 60137571113 - 210 = 60137570089 is a prime.
It is a super-2 number, since 2×601375711132 (a number of 22 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (60137571133) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 30068785556 + 30068785557.
It is an arithmetic number, because the mean of its divisors is an integer number (30068785557).
Almost surely, 260137571113 is an apocalyptic number.
It is an amenable number.
60137571113 is a deficient number, since it is larger than the sum of its proper divisors (1).
60137571113 is an equidigital number, since it uses as much as digits as its factorization.
60137571113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 13230, while the sum is 35.
The spelling of 60137571113 in words is "sixty billion, one hundred thirty-seven million, five hundred seventy-one thousand, one hundred thirteen".
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