Base | Representation |
---|---|
bin | 101011111001111001100… |
… | …1100000111101100110111 |
3 | 210100212100202110011002201 |
4 | 1113303303030013230313 |
5 | 1242331032303434333 |
6 | 20500025114245331 |
7 | 1161646310525626 |
oct | 127636314075467 |
9 | 23325322404081 |
10 | 6034214124343 |
11 | 1a1710661a479 |
12 | 81557a126847 |
13 | 34a0408077a2 |
14 | 16c0b3ba96bd |
15 | a6e6ca3117d |
hex | 57cf3307b37 |
6034214124343 has 16 divisors (see below), whose sum is σ = 6305123897280. Its totient is φ = 5764019222016.
The previous prime is 6034214124329. The next prime is 6034214124397. The reversal of 6034214124343 is 3434214124306.
It is a de Polignac number, because none of the positive numbers 2k-6034214124343 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (6034214124443) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 150170671 + ... + 150210847.
It is an arithmetic number, because the mean of its divisors is an integer number (394070243580).
Almost surely, 26034214124343 is an apocalyptic number.
6034214124343 is a deficient number, since it is larger than the sum of its proper divisors (270909772937).
6034214124343 is a wasteful number, since it uses less digits than its factorization.
6034214124343 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 48906.
The product of its (nonzero) digits is 165888, while the sum is 37.
Subtracting from 6034214124343 its sum of digits (37), we obtain a palindrome (6034214124306).
Adding to 6034214124343 its reverse (3434214124306), we get a palindrome (9468428248649).
The spelling of 6034214124343 in words is "six trillion, thirty-four billion, two hundred fourteen million, one hundred twenty-four thousand, three hundred forty-three".
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