6036864134471 has 4 divisors (see below), whose sum is σ = 6135829120344. Its totient is φ = 5937899148600.

The previous prime is 6036864134461. The next prime is 6036864134513. The reversal of 6036864134471 is 1744314686306.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-6036864134471 is a prime.

It is a super-3 number, since 3×6036864134471³ (a number of 39 digits) contains 333 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (6036864134461) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 49482492845 + ... + 49482492966.

It is an arithmetic number, because the mean of its divisors is an integer number (1533957280086).

Almost surely, 2^{6036864134471} is an apocalyptic number.

6036864134471 is a gapful number since it is divisible by the number (61) formed by its first and last digit.

6036864134471 is a deficient number, since it is larger than the sum of its proper divisors (98964985873).

6036864134471 is an equidigital number, since it uses as much as digits as its factorization.

6036864134471 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 98964985872.

The product of its (nonzero) digits is 6967296, while the sum is 53.

The spelling of 6036864134471 in words is "six trillion, thirty-six billion, eight hundred sixty-four million, one hundred thirty-four thousand, four hundred seventy-one".