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6040314113 is a prime number
BaseRepresentation
bin1011010000000011…
…11110000100000001
3120120221220202020112
411220001332010001
544332310022423
62435212521105
7302453552141
oct55001760401
916527822215
106040314113
11261a666439
121206a80195
13753542582
14414304921
1525544ca78
hex16807e101

6040314113 has 2 divisors, whose sum is σ = 6040314114. Its totient is φ = 6040314112.

The previous prime is 6040314107. The next prime is 6040314131. The reversal of 6040314113 is 3114130406.

Together with next prime (6040314131) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 5747459344 + 292854769 = 75812^2 + 17113^2 .

It is a cyclic number.

It is not a de Polignac number, because 6040314113 - 214 = 6040297729 is a prime.

It is not a weakly prime, because it can be changed into another prime (6040314173) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3020157056 + 3020157057.

It is an arithmetic number, because the mean of its divisors is an integer number (3020157057).

Almost surely, 26040314113 is an apocalyptic number.

It is an amenable number.

6040314113 is a deficient number, since it is larger than the sum of its proper divisors (1).

6040314113 is an equidigital number, since it uses as much as digits as its factorization.

6040314113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 864, while the sum is 23.

The square root of 6040314113 is about 77719.4577502957. The cubic root of 6040314113 is about 1821.1812676111.

Adding to 6040314113 its reverse (3114130406), we get a palindrome (9154444519).

The spelling of 6040314113 in words is "six billion, forty million, three hundred fourteen thousand, one hundred thirteen".