Base | Representation |
---|---|
bin | 1011010000010010… |
… | …11000111110000111 |
3 | 120121002120120120210 |
4 | 11220021120332013 |
5 | 44333304244320 |
6 | 2435322330503 |
7 | 302506233300 |
oct | 55011307607 |
9 | 16532516523 |
10 | 6042259335 |
11 | 2620774962 |
12 | 1207659a33 |
13 | 753a73aa8 |
14 | 41468d7a7 |
15 | 2556d40e0 |
hex | 168258f87 |
6042259335 has 48 divisors (see below), whose sum is σ = 11281912416. Its totient is φ = 2753356032.
The previous prime is 6042259319. The next prime is 6042259351. The reversal of 6042259335 is 5339522406.
6042259335 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is an interprime number because it is at equal distance from previous prime (6042259319) and next prime (6042259351).
It is not a de Polignac number, because 6042259335 - 24 = 6042259319 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 6042259293 and 6042259302.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 220029 + ... + 245961.
It is an arithmetic number, because the mean of its divisors is an integer number (235039842).
Almost surely, 26042259335 is an apocalyptic number.
6042259335 is a deficient number, since it is larger than the sum of its proper divisors (5239653081).
6042259335 is a wasteful number, since it uses less digits than its factorization.
6042259335 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 26272 (or 26265 counting only the distinct ones).
The product of its (nonzero) digits is 194400, while the sum is 39.
The square root of 6042259335 is about 77731.9711251426. The cubic root of 6042259335 is about 1821.3767442912.
The spelling of 6042259335 in words is "six billion, forty-two million, two hundred fifty-nine thousand, three hundred thirty-five".
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